Django shell
$ tree
.
├── core
│ └── models.py
│ ...
└── manage.py
...
1 directory, 2 files
打开你本地的终端(不是在Python解析器里面) 然后输入这个命令:
$ python manage.py shell
Python 2.7.10 (default, Feb 22 2019, 21:55:15)
[GCC 4.2.1 Compatible Apple LLVM 10.0.1 (clang-1001.0.37.14)] on darwin
Type "help", "copyright", "credits" or "license" for more information.
(InteractiveConsole)
>>>
>>> from .core import models
>>> models.Channel.objects.all()
<QuerySet [<Channel: Channel object>, <Channel: Channel object>, <Channel: Channel object>, <Channel: Channel object>, <Channel: Channel object>, <Channel: Channel object>, <Channel: Channel object>, <Channel: Channel object>, <Channel: Channel object>, <Channel: Channel object>, <Channel: Channel object>, <Channel: Channel object>, <Channel: Channel object>, <Channel: Channel object>, <Channel: Channel object>]>
类似的，这里也是通过 from xxx import xxx 语句引用一个模块，所以可以直接调用 models 模块的方法，即通过 [方法名]()，而方法名前不再需要声明该方法所属的模块。
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